Question

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Answer 1

I think you're wrong on A because its 10 every year meaning its going at a constant rate

Answer 2

If you're willing to answer some questions, I'd be happy to provide you with some guidance in solving this problem.
1. What's the original value of the computer?
2. After depreciating 10% during the entire first year, the computer is worth 10% less. How much is it worth? That's the amount it's worth at the beginning of the 2nd year.
3. How does one get from the initial value (at the beginning of year #1) to the initial value at the beginning of year #2? to the initial value at the beginning of year #3?

Answer 3

Mathmale is a better teacher than I am >.<

Answer 4

.______. but that's how you'll learn it U_U

Answer 5

.-.

Answer 6

Arithmetic series involve the addition of a constant to every term. Is that happening here?

Answer 7

Geometric series involve creating a new term in a sequence by multiplying the previous one by some constant. So... care to try again to "name that sequence"?

Answer 8

How did you get C if you don't have a formula for B..? Unless you went 1 by 1 :o

Answer 9

I'd much prefer not to give you "right" or "wrong" answers. I'd be glad to respond to your "is the formula 1250(0.9)^n?" question if you'd please explain how you got it and what kind of sequence this is.

Answer 10

Note that your peer (tHe_FiZiCx99) is also asking you to explain how you decided on Choice C.

Answer 11

That's a very sensible answer, and I appreciate your explanation.

"is the formula 1250(0.9)^n?" Yes, 'though it could be improved by putting in a " $ " sign and saying what the starting value of n is. What do YOU think n starts with?

Answer 12

" n " here is a "counter" and begins with the value zero ( 0 ).
If the formula is $1250(0.9)^n, and n=0, what would the initial value of the computer be?

Answer 13

Well, 0.9^0 = ?