Mathematics
13 Online
OpenStudy (anonymous):
SOLVE THE QUESTION
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[X ^{X}+^{Y} =Y ^{3} AND Y ^{X}+^{Y} = X ^{6}Y ^{3}\]
OpenStudy (anonymous):
THIR IS SPACE AFTER AND
OpenStudy (anonymous):
AND X AND Y AREnatural numbers
OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
Uh, what are we suppose to solve?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
the value for y raise to the power x is equal to what
OpenStudy (anonymous):
this must be sixth sense
ganeshie8 (ganeshie8):
\(\large X^{X+Y} =Y ^{3} \)
\(\large Y^{X+Y} = X ^{6}Y ^{3}\)
ganeshie8 (ganeshie8):
like that ?
OpenStudy (yttrium):
I think ^
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
YUP
ganeshie8 (ganeshie8):
\(x=y=1\) is a tivial solution
OpenStudy (anonymous):
i simple words ??????????????|
OpenStudy (anonymous):
Yeah x = 1, y = 1
OpenStudy (anonymous):
but how
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
\(x=y=1\) is an easy solution,
not sure if there can be other solutions also, if thre are no other solutions, we need to prove it as well ok
OpenStudy (anonymous):
There can't be
OpenStudy (anonymous):
but we have to find \[Y ^{X}\]
OpenStudy (anonymous):
IS EQUAL TO WHAT
ganeshie8 (ganeshie8):
oh ok.. that simplifies a bit..
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (ikram002p):
i tried this
\(y^(-x-y) × x^(x+y)=y^0x^6\)
ganeshie8 (ganeshie8):
ikam use {} for exponent..
OpenStudy (ikram002p):
-_-"
OpenStudy (ikram002p):
\(\Huge{x^{-x-y} y^{x+y}=x^6y^0}\)
OpenStudy (anonymous):
DUDE YOU NEED TO EXPLAIN ME HOW YOU GOT THIS
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
divide the two equations
OpenStudy (ikram002p):
even thought if i explain this , the oly solution u
cud got is 1,1 (bye trial)
else wont work
ganeshie8 (ganeshie8):
but we need to find the value of \(y^x\),
not the actual solutions...
OpenStudy (anonymous):
the answer is one 1
OpenStudy (anonymous):
He just made them equal don, but that's not what we need
Join the QuestionCove community and study together with friends!
Sign Up
ganeshie8 (ganeshie8):
if we can prove that x=y=1 are the oly solutions possible,
then that also means that y^x = 1
so either way is fine
OpenStudy (usukidoll):
proof problem?
OpenStudy (usukidoll):
well why couldn't we just do that? x = 1 y =1 problem ended.
OpenStudy (anonymous):
OK THE ANSWER IS Y^X = 1 GANESHIE8 HAS SAID IT!
OpenStudy (anonymous):
Move on don, move on!
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yes
ganeshi said than said no more queries
ganeshie8 (ganeshie8):
ive said it - but terms and conditions apply :)
ganeshie8 (ganeshie8):
you still need to prove, why other solutions dont exist ok
OpenStudy (anonymous):
yes terms and conditions apply
OpenStudy (anonymous):
like i said ganeshi said than ganeshie said
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (ikram002p):
\(y^{x+y}=x^6(x^xx^y)\)
ughh no sense in any prove :o
OpenStudy (ikram002p):
*proof
OpenStudy (anonymous):
|dw:1392460101309:dw|