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Mathematics 8 Online
OpenStudy (anonymous):

Lines CD and DE are tangent to circle A as shown below:

OpenStudy (anonymous):

OpenStudy (anonymous):

If CE is 130°, what is the measure of ∠CDE? (5 points) Select one: a. 20° b. 40° c. 42.5° d. 50°

OpenStudy (anonymous):

Like i dont get this i thought i would be able to tell

OpenStudy (gudden):

lemme give u a hint.. join CA and AE

OpenStudy (anonymous):

THAT WAS A HELL OF A SHOW WE PUT THEIR

OpenStudy (gudden):

now don't start here @donmath ... till i explain him this question...

OpenStudy (anonymous):

|dw:1392466189038:dw|

OpenStudy (anonymous):

i think i messed up

OpenStudy (anonymous):

is it not going to be a decimal

OpenStudy (anonymous):

so we can just cancel out one answer

OpenStudy (gudden):

@prowrestler ... since the line joining the tangent the radius is perpendicular therefore in the quadrilateral thus formed.. two anles are 90 degrees and one is 130 degrees so then u could use the angle sum property of quadrilateral which states that sum of all the angles of a quadrilateral is 360 degree here u go u could use this diagram for help |dw:1392466316308:dw|

OpenStudy (gudden):

@prowrestler .. try now..

OpenStudy (anonymous):

u just explained it soo much easier

OpenStudy (gudden):

so what is the answer...@prowrestler

OpenStudy (anonymous):

what do i do do i take half f

OpenStudy (anonymous):

is it 50 or 42.5

OpenStudy (gudden):

its 50..

OpenStudy (anonymous):

ok thank you i get it :)

OpenStudy (gudden):

:D.. ur welcome..

OpenStudy (anonymous):

A hot air balloon holds 4,328 cubic meters of helium. The density of helium is 0.9874 kilograms per cubic meter. How many kilograms of helium does the balloon contain, rounded to the nearest tenth of a kilogram? (5 points) Select one: a. 3,747.9 kg b. 3,875.3 kg c. 4,273.5 kg d. 4,383.2 kg

OpenStudy (anonymous):

what about this one

OpenStudy (gudden):

its the same as the last question...

OpenStudy (gudden):

i mean the method of solving it.

OpenStudy (anonymous):

i know

OpenStudy (anonymous):

do i have to draw anything

OpenStudy (gudden):

no u don't have to draw something

OpenStudy (anonymous):

oh ok can you explain what i do then:)

OpenStudy (anonymous):

@ganeshie8

ganeshie8 (ganeshie8):

\(\large \mathbb{Mass = (density) \times ( volume)}\)

ganeshie8 (ganeshie8):

read the question, and figure out wat quantities are given

ganeshie8 (ganeshie8):

when u goto shop, the shop owner wud ask u : how many kilograms of sugar you want ?

ganeshie8 (ganeshie8):

wat he is asking ?

OpenStudy (anonymous):

4,328 cubic meters of helium.

OpenStudy (anonymous):

The density of helium is 0.9874 kilograms per cubic meter.

ganeshie8 (ganeshie8):

0.9874 is \(density\)

ganeshie8 (ganeshie8):

wat about 4328 cubic meters of helium ? is it \(Volume\) or \(Mass\) ?

OpenStudy (anonymous):

is it the volume

ganeshie8 (ganeshie8):

yes, Cubic meters, Cubic centimeters all are volumes... a 500cc motorbike has a cylinder-volume of 500cc

ganeshie8 (ganeshie8):

plug that in the formula

OpenStudy (anonymous):

where is the formula srr:(

ganeshie8 (ganeshie8):

\(\large \mathbb{Mass = (density) \times ( volume)} \)

ganeshie8 (ganeshie8):

just multiply the given two quantities

OpenStudy (anonymous):

0.9874 * 4328

ganeshie8 (ganeshie8):

yes

OpenStudy (anonymous):

4273.4672

ganeshie8 (ganeshie8):

\(\huge \mathbb{\color{red}{\checkmark}}\)

OpenStudy (anonymous):

So the answer is C

ganeshie8 (ganeshie8):

\(\large \mathbb{\color{red}{\checkmark}\color{red}{\checkmark}}\)

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