Water flows in and out of a storage tank. A graph of the rate of change r(t) of the volume of water in the tank, in liters per day, is shown. Time t is measured in days. If the amount of water in the tank at time t = 0 is 25000 L, use the Midpoint Rule with n = 4 to estimate the total amount of water (in liters) in the tank four days later. https://webwork.math.uwosh.edu/webwork2_files/tmp/Spring2014-Math172-szydliks/img/b41ce338-971f-35a5-8432-a3760a3f44da___c7a28249-003e-3dfe-b6a2-fe9514a04f7b.gif
Anyone help?
total amount of water in the tank = 25000 + area under the gaph
area under graph = \(\large 1[f(0.5) + f(1.5) + f(2.5) + f(3.5)]\)
ok thank you soooo much! i didn't understand how to use the 25000
area under graph = \(\large 1[1500 + 1750 + 750 -750]\)
np :)
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