Question

one more question please' see attachment

Answer 1

i know that there are right triangles do i use a^2+b^2=c^2 ??

Answer 2

yes to find diameter and then PS

Answer 3

yes, twice you'll need to use Pythagoras theorem

Answer 4

so like this?
\[14^2+8^2=4r^2\]

Answer 5

(PR) ^2

Answer 6

yes, thats correct though.

Answer 7

\[r=\sqrt{65}\]

Answer 8

PS^2+RS^2 = 4r^2 too

Answer 9

yes, r = that, though not required, but its ok if you found it.

Answer 10

PS^2+RS^2 = 4r^2
find PS from this

Answer 11

\[PS^2+9=4r^2\] ??

Answer 12

yes, go ahead

Answer 13

is this right now
\[PS^2-4r^2+9\]

Answer 14

you know the value of 4r^2 , since you know r

Answer 15

4r^2 = 260

Answer 16

r=\[\sqrt{65}\] ok yes got that answer in book is saying PS =\[\sqrt{251}\] how

Answer 17

because we need PS , not the radius

Answer 18

PS^2 = 4r^2 - RS^2 = 260 - 9 = 251
PS = sqrt 251

Answer 19

oh wow so sorry !!! duh !

Answer 20

no problem! :)

Answer 21

guess i overthinking it lol