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OpenStudy (anonymous):
42.55mL of a standardized 1.005 M NaOH solution was necessary to exactly neutralize 30.0mL of an aqueous H2SO4 solution of unknown concentration. What is the molarity of the H2SO4 solution?
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OpenStudy (wolfe8):
First, write out the balanced equation for this neutralization.
OpenStudy (anonymous):
Is the answer along the lines of M1*V1=M2*V2 1.005 mol NaOH * 42.55 mL NaOH = ??? * 30.0 mol H2SO4 Making the molarity of H2SO4 equal to 1.425?
OpenStudy (anonymous):
The balanced equation should be along the lines of 2NaOH + H2SO4 --> Na2SO4 + H2O right?
OpenStudy (wolfe8):
It's not balanced. But you will use n=mV where n is the number of moles and m is the concentration.
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