Question

42.55mL of a standardized 1.005 M NaOH solution was necessary to exactly neutralize 30.0mL of an aqueous H2SO4 solution of unknown concentration. What is the molarity of the H2SO4 solution?

Answer 1

First, write out the balanced equation for this neutralization.

Answer 2

Is the answer along the lines of
M1*V1=M2*V2
1.005 mol NaOH * 42.55 mL NaOH = ??? * 30.0 mol H2SO4
Making the molarity of H2SO4 equal to 1.425?

Answer 3

The balanced equation should be along the lines of
2NaOH + H2SO4 --> Na2SO4 + H2O
right?

Answer 4

It's not balanced. But you will use n=mV where n is the number of moles and m is the concentration.