Evaporation of sweat is the human body's cooling mechanism. At body temperature, it takes 2.4 MJ/kg to evaporate water. Marathon runners typically lose about 3 L of sweat each hour.How much energy gets lost to sweating during a 1.7-hour marathon?
This is my work: total mass of sweat: 3*1.7 = 5.1L = 5.1kg Heat-loss : Q = mL = 5.1 kg* 2.4*10^6 J/kg = 1.224*10^8 J and then, energy P = Q/t = 7.2 *10^6 J/s Am I right? @ybarrap
oh, no, P = Q/t = 1.224*10^8 J/ 6120s = 20000J/s= 20kJ/s
The only problem I see is that P is power not energy. Q is what you are looking for.
"'How much energy gets lost " You already found that. You went too far. Energy is a quantity in joules, NOT joules per second... that'd be a rate of energy usage/production.
:) so, it's just Q? how about P in P = Q/t ? what is it?
Power = energy/time
That is power, rate of change of energy per unit time
Thanks you all. :)
That is very easy to confuse. You walk a mile, you run a mile. You use the same amount of energy. But power is different in each case.
because the time used in walking is longer than it is in running, right?
Yes so power will be lower when walking.
Thank you. :)
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