Mathematics
10 Online
OpenStudy (anonymous):
Pls help me solve, thanks
Find the distance d(P1 and P2) between the points P1 and P2
P1 = (-2, 5) P2 = (1,4)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\[d=\sqrt{(x2-x1)^2+(y2-y1)^2}\]
OpenStudy (anonymous):
Thanks. Not good at square roots but this will do. Thanks
OpenStudy (anonymous):
is the ans the square root of -5?
OpenStudy (anonymous):
that is 2.24
OpenStudy (anonymous):
I got \[\sqrt{10}\]
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
uhmm will try it again but thanks.
OpenStudy (anonymous):
1-(-2) = 3; 3^2 = 9
4-5 = -; -1^2 = 1
sqrt(9+1) = sqrt(10)
OpenStudy (anonymous):
*4-5= -1
OpenStudy (anonymous):
Lets say you use 2 as x2 and 1 as x1...the same for the y's.
(You should get the same thing)
OpenStudy (anonymous):
ok.... trying again
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
-2-1 = -3; -3^2 = 9
5-4 =1 1^2= 1
sqrt(9+1) = sqrt(10)
You should get sqrt(10) either way
OpenStudy (anonymous):
Don't sqaure right away, do subtraction first
OpenStudy (anonymous):
I did this time thanks!!
OpenStudy (anonymous):
got it. :)
OpenStudy (anonymous):
I think you were doing sqrt(1- (-2)^2); resulting in sqrt(1-4) instead of sqrt(-3^2)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
that was what i did. you are right
OpenStudy (anonymous):
|dw:1392516969518:dw|