Pls help me solve, thanks Find the distance d(P1 and P2) between the points P1 and P2 P1 = (-2, 5) P2 = (1,4)
\[d=\sqrt{(x2-x1)^2+(y2-y1)^2}\]
Thanks. Not good at square roots but this will do. Thanks
is the ans the square root of -5?
that is 2.24
I got \[\sqrt{10}\]
uhmm will try it again but thanks.
1-(-2) = 3; 3^2 = 9 4-5 = -; -1^2 = 1 sqrt(9+1) = sqrt(10)
*4-5= -1
Lets say you use 2 as x2 and 1 as x1...the same for the y's. (You should get the same thing)
ok.... trying again
-2-1 = -3; -3^2 = 9 5-4 =1 1^2= 1 sqrt(9+1) = sqrt(10) You should get sqrt(10) either way
Don't sqaure right away, do subtraction first
I did this time thanks!!
got it. :)
I think you were doing sqrt(1- (-2)^2); resulting in sqrt(1-4) instead of sqrt(-3^2)
that was what i did. you are right
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