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Calculate the number of grams of Fe formed when 0.370kg of Fe2O3 reacts.
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Welcome to OpenStudy. First you will need the balanced chemical equation.
Calculate the number of grams of Fe formed when 0.370kg of Fe2O3 reacts. I will assume that all the Fe from the compound is converted to Fe. The Molecular mass of Fe2O3 is 159.688 and the amount of Fe is 111.69 g/mol, we can make a conversion factor and multiply the mass (370g) 370g Fe2O3 x 111.69 Fe / 159.688 g Fe2O3 = 258.78 g Since the compound has 69.94% of Fe that's means that 69.94% of 370g will be the maximum amount of Fe that you can obtain. That is aprox 370 x 69.94 / 100 = 259g. 2Fe2O3 -> 4Fe + 3O2
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