Question

Prove that the magnitude of the resultant of two equal forces in magnitude acting at one point and the angle between them is 20 , is equal in magnitude to each force

Answer 1

Do you mean 120?

Answer 2

\[|C| = \sqrt{|A|^2 + |B|^2 + 2|A||B|\cos(\theta)}\]Well, that formula's a start.

Answer 3

Yes Im sorry

Answer 4

Then ?

Answer 5

Oh, sorry. Uh -- so the magnitudes of \(A\) and \(B\) are equal and \(\theta = 120\).

Answer 6

Okaai I did that
And then how can i get the two resultant ?

Answer 7

Use the value \(\cos(120) = \dfrac{-1}{2}\)

Answer 8

i did that :)

Answer 9

Please write the complete answer cause i want to ask alot of questions

Answer 10

\[|C| = \sqrt{A^2 + A^2 + 2|A|^2\cdot \dfrac{-1}{2}} = \sqrt{|A|^2}\]

Answer 11

hmm

Answer 12

Uh, wouldn't that... suffice?

Answer 13

What is \(\sqrt{|A|^2}\)

Answer 14

I dont know :/

Answer 15

What is the square root of the square?

Answer 16

i dont understand you