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Simplify to lowest terms: 1/2(2x + y)(4z)
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@shamil98
Distribute it out..
I pretty much understand how the answer explains it. But I don't get why they wouldn't cross out 2 even if the denominator was 2, but crossed out 4 to 2, making it 2z(2x+y)
\[\frac{ 1 }{ 2 } (2x+y)(4z) = \frac{ (2x+y)(4z) }{ 2 } = 2z(2z+y)\]
Why are there two z's?
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a typo that should be 2z(2x+y)
But why shouldn't 2 cross out 2?
You can take two out of the numerator, so you can cross off the two in the denominator.
Because there the denominator is reduced to 1.. you haven't anything to reduce it by ..
\[\frac{ 1 }{ \cancel 2 } (2x+y) (\cancel 4 2z) =(2x+y)(2z)\]
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Okay. It's clear to me now. Thanks.
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