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Mathematics 15 Online
OpenStudy (lukecrayonz):

Statistics word problem! :) http://puu.sh/6Z5pY.png

OpenStudy (lukecrayonz):

@jim_thompson5910

OpenStudy (anonymous):

This seems to me like a binomial distribution problem.

OpenStudy (lukecrayonz):

It is! It's what I'm learning right now but I'm not 100% on it:)

OpenStudy (anonymous):

What did you get for the first bullet?

OpenStudy (anonymous):

Also, do you have a probability distribution chart for when n = 50 for this?

OpenStudy (lukecrayonz):

No i don't, this is all that was given. I just started taking statistics and this is my 2nd assignment haha so please understand i don't understand a lot

OpenStudy (anonymous):

No worries. I was just wondering because that would make some of these parts much easier to calculate. The formula we are using is \[\left(\begin{matrix}n \\ x\end{matrix}\right)p^xq ^{n-x}\]

OpenStudy (lukecrayonz):

I know this is coming back to me it's something like (0.24)^n*(0.76)^n-x

OpenStudy (lukecrayonz):

Right!

OpenStudy (lukecrayonz):

So what is n? 50?

OpenStudy (lukecrayonz):

so that it would be (0.24)^10*(0.76)^40?

OpenStudy (anonymous):

Yes. The variable n represents the number of trials, which in this case is 50. That's right.

OpenStudy (lukecrayonz):

I was doing this and I had a problem with something so maybe you can help with that! On the 2nd bullet point it says it at least 10. I understand I have to do the ^0 up to ^10 but it takes so long, is there a shorter way to do it?

OpenStudy (lukecrayonz):

(0.24)^10*(0.76)^40 I know that's wrong because I'm getting over one, so what am I doing wrong?

OpenStudy (anonymous):

The number .24^10 * .76^40 is not greater than 1

OpenStudy (anonymous):

I'm getting 1.083068...*10^(-11) which is definitely less than 1.

OpenStudy (anonymous):

Remember that you have to multiply by \[\left(\begin{matrix}50 \\ 10\end{matrix}\right)\]

OpenStudy (lukecrayonz):

Oh whoops! That's correct sorry:)

OpenStudy (lukecrayonz):

Okay so for #2 of it, it says less than 10. Do I have to do all of them or is there a way to do it without having to multiply them all out?

OpenStudy (anonymous):

Without a distribution chart, the fastest way I know to do it is to add up all the probabilities 1 through 9 and subtract that value from 1.

OpenStudy (anonymous):

Look at this page and scroll down to n = 50.

OpenStudy (anonymous):

Well actually, they don't have our .24 probability of success. Hold on.

OpenStudy (lukecrayonz):

Uh oh :P haha

OpenStudy (anonymous):

http://stattrek.com/online-calculator/binomial.aspx

OpenStudy (anonymous):

Check that out though. It does all the work for you. Remember that when we are talking about at least 10, we mean >= 10

OpenStudy (lukecrayonz):

what should I put for "number of success?"

OpenStudy (lukecrayonz):

0.24?

OpenStudy (anonymous):

10

OpenStudy (anonymous):

At least for bullets 1 - 3

OpenStudy (lukecrayonz):

so it would be bullet 1: 0.111255856065322 bullet 2: 0.206550433838689 bullet 3: 0.317806289904011

OpenStudy (lukecrayonz):

and bullet 4: 0.11628996701893859

OpenStudy (lukecrayonz):

Sorry for slow responses, openstudy doesn't like my computer @RBauer4

OpenStudy (anonymous):

bullet 2 should be .7934.... , and bullet 1 and bullet 3 are correct.

OpenStudy (anonymous):

At least implies greater than or equal to

OpenStudy (lukecrayonz):

OOo i did x>10 not x<10

OpenStudy (lukecrayonz):

Wording was weird :) and bullet 4 I should do x=21 and x=45 and just add them

OpenStudy (lukecrayonz):

0.0022710274978721500000691282565252491

OpenStudy (lukecrayonz):

That doesn't seem right to me haha

OpenStudy (anonymous):

Well, if you think about it. You practically have a probability of 1 considering the cumulative probability less than 45

OpenStudy (lukecrayonz):

Ooooh right then 0.002271.... would be considered "unusual"

OpenStudy (anonymous):

Thus, we are only really calculating the probability when x is strictly greater than 20

OpenStudy (lukecrayonz):

So 0.11, 0.7934, 0.317, 0.11 and 0.0027

OpenStudy (anonymous):

I think the last bullet would be 0.003769047260403 and I'm not sure for the 4th yet

OpenStudy (anonymous):

And I believe bullet four is 0.78968051890090805

OpenStudy (anonymous):

I must go now. Good luck in your studies

OpenStudy (lukecrayonz):

thanks!

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