What is the discontinuity and zero of the function f(x) = 2x^2+5x-12/x+4? Discontinuity at (-4, -11), zero at (3/2 , 0) Discontinuity at (-4, -11), zero at (- 3/2 , 0) Discontinuity at (4, 5), zero at ( 3/2, 0) Discontinuity at (4, 5), zero at (-3/2 , 0)
Anybody know? @Kainui
@jim_thompson5910
@MathLegend @mathmale
@Mertsj
@wio
Can the denominator be 0?
no those are the responses up above! @Mertsj
i just really need help with this problem! @Mertsj @wio
http://www.wolframalpha.com/input/?i=graph%3Af%28x%29+%3D+2x^2%2B5x-12%2F%28x%2B4%29
So it would be out of the list of answer choices it would be either the first or second one! @Mertsj
first one
thank you!
yw
@Mertsj Here is another one if you could help me with it!
What are the zero(s) of the function f(x)=4x^2-36x/x-9
Factor the numerator
@Mertsj answer choices! x = -9 x = 0 x = 9 x = 0 and x = 9
\[\frac{4x^2-36x}{x-9}\]
Is that the problem?
yup!
Factor the numerator
Elaborate @Mertsj
The numerator is 4x^2-36x Factor out 4x
x^2 -9
4x(x^2-9) Does that = 4x^2-36x?
yes? @Mertsj
What is 4x multiplied by x^2
4x^3 @Mertsj
Then I guess those could not be the factors because there is on 4x^3 in your problem so factor the numerator and this time makes sure the factors multiply back
Um i dont understand? can you explain it to me? @Mertsj
You are working on a pre calc test. You need to discover on your own how to factor out the common factor from 4x^2-36x.
That is an algebra 1 problem
isint it 0 and 9
@Mertsj
The denominator is x-9 so x cannot be 9
Then it is 0 @Mertsj
?? @Mertsj
correct @Mertsj
Please note that the original problem: f(x) = 2x^2+5x-12/x+4? You have written: \(f(x) = 2x^{2} + 5x - \dfrac{12}{x} + 4\) If that is not your intent, please remember your Order of Operations and use parentheses as necessary.
Distributive Property of Multiplication over Addition. a(b+c) = ab + ac or the other way ab + ac = a(b+c) \( 4x^2-36x = 4(x^{2} - 9x)\) Do the same with the constant factor "x".
ok but wouldnt that cause for the answers to be equal to 0 or no?
* common factor, not constant factor. Sorry about that.
I don't actually care what the answers are, just yet. I want to SEE it factored and WRITTEN. Then we can worry about the final solution.
Oh ok I am sorry! @tkhunny
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