Question

how do you find the maximum or minimum -8x^2-16x+6

Answer 1

DO you need to use Calculus here?

Answer 2

because there are 2 ways to solve this.

Answer 3

-7x^2-14x+3 this is the question I meant to put

Answer 4

Again, there are two ways to do this. We can either use the nature of the quadratic or use derivatives. Which way do you want to do?

Answer 5

quadratic

Answer 6

Have you learnt Calculus?

Answer 7

yes

Answer 8

@Dido525 how are u?

Answer 9

Lets use Calculus then :P Much quicker. Can you take the derivative of that?

Answer 10

no

Answer 11

Negative leading coefficient, parabola opens down. It has a maximum but no minimum.
To find the x coordinate of the vertex (maximum) use -b/2a
To find the y coordinate of the vertex, plug the x you just solved for back into the original equation.

Answer 12

I already know the vertex

Answer 13

Max, no min

Answer 14

the max isn't -1,10 I typed it and it marks it wrong

Answer 15

Alright.

Answer 16

Find the zeros of that quadratic.

Answer 17

Can you do that?

Answer 18

i get decimals

Answer 19

That's okay.

Answer 20

The maximum occurs halfway between those points.