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Mathematics 8 Online
OpenStudy (anonymous):

Here is the new question!

OpenStudy (anonymous):

@wio

OpenStudy (anonymous):

when is the denominator \(0\)? That is where the whole should be.

OpenStudy (anonymous):

What do you mean?

OpenStudy (anonymous):

The denominator, the bottom part. When does it become 0? That is where the function has a hole.

OpenStudy (anonymous):

ok?

OpenStudy (anonymous):

ok and how does that have to do with the question? @wio

OpenStudy (anonymous):

the graphs have holes in them....

OpenStudy (anonymous):

If you knew which one had the right hole, you would have the solution...

OpenStudy (anonymous):

ok !

OpenStudy (anonymous):

so continue! @wio

OpenStudy (anonymous):

wouldnt i have to solve for the equation @wio

OpenStudy (anonymous):

right? @wio

OpenStudy (anonymous):

What, I already explained it...

OpenStudy (anonymous):

is the hole at 1 or -1?

OpenStudy (anonymous):

-1 @wio

OpenStudy (anonymous):

Good. Now let \(x=0\) and find the \(y\) intercept.

OpenStudy (anonymous):

That will tell you what value it should be when it hits the y axis.

OpenStudy (anonymous):

2? @wio

OpenStudy (anonymous):

No

OpenStudy (anonymous):

or 1? @wio

OpenStudy (anonymous):

show your work

OpenStudy (anonymous):

Is it 1?

OpenStudy (anonymous):

Are you trying to make me angry?

OpenStudy (anonymous):

Plug \(x=0\). What do you get?

OpenStudy (anonymous):

Excuse you? I am just asking ok?

OpenStudy (anonymous):

I never did anything to disrespect you ok?

OpenStudy (anonymous):

Well, you are playing this guess and check game, even though I asked for you to show me your work.

OpenStudy (anonymous):

Ok but I am just asking and that happens! That is there people like you to help students like us to be able to solve it!

OpenStudy (anonymous):

wait just to be clear it would be 0-1=y right?

OpenStudy (anonymous):

no, we have \[ y = \frac{4x^2-4x-8}{2x+2} \]

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

then we let \(x=0\)

OpenStudy (anonymous):

oh ok i apoligize!

OpenStudy (anonymous):

I wasn't being serious.

OpenStudy (anonymous):

oh ok! really, you did that to make me show the work! :)

OpenStudy (anonymous):

i get -4!

OpenStudy (anonymous):

@wio

OpenStudy (anonymous):

Yeah. So we can now do elimination. We know there is a hole at \(x=-1\) and it goes through the \(y\) axis at \(y=-4\).

OpenStudy (anonymous):

yup!

OpenStudy (anonymous):

would it be the second answer @wio

OpenStudy (anonymous):

but the second one has a hold at \(x=1\) so it can't be right.

OpenStudy (anonymous):

the third one @wio

OpenStudy (anonymous):

Guessing again?

OpenStudy (anonymous):

Does the third one go through \(y\) at \(-4\)?

OpenStudy (anonymous):

no the x=-1

OpenStudy (anonymous):

nevermind its the 4th one? i have to be right!

OpenStudy (anonymous):

@wio

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

@wio

OpenStudy (anonymous):

does the 4th one go through \(4\) when it intersects with \(y\) axis?

OpenStudy (anonymous):

no?

OpenStudy (anonymous):

then the 4th one can't be right.

OpenStudy (anonymous):

its the first one! @wio

OpenStudy (anonymous):

Yes...

OpenStudy (anonymous):

ok i did the next one and i already eliminated the last two answers

OpenStudy (anonymous):

@wio

OpenStudy (anonymous):

it already plugged in 0 and got the answer that it is -6

OpenStudy (anonymous):

@wio

OpenStudy (anonymous):

right? or at least @UsukiDoll can you help me out here

OpenStudy (anonymous):

hello @UsukiDoll

OpenStudy (agent0smith):

^post a new question for a new question. More people see it. Question doesn't get messy.

OpenStudy (anonymous):

@UsukiDoll Can you help me out!

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