Mathematics
8 Online
OpenStudy (anonymous):
Here is the new question!
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OpenStudy (anonymous):
@wio
OpenStudy (anonymous):
when is the denominator \(0\)? That is where the whole should be.
OpenStudy (anonymous):
What do you mean?
OpenStudy (anonymous):
The denominator, the bottom part. When does it become 0? That is where the function has a hole.
OpenStudy (anonymous):
ok?
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OpenStudy (anonymous):
ok and how does that have to do with the question? @wio
OpenStudy (anonymous):
the graphs have holes in them....
OpenStudy (anonymous):
If you knew which one had the right hole, you would have the solution...
OpenStudy (anonymous):
ok !
OpenStudy (anonymous):
so continue! @wio
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OpenStudy (anonymous):
wouldnt i have to solve for the equation @wio
OpenStudy (anonymous):
right? @wio
OpenStudy (anonymous):
What, I already explained it...
OpenStudy (anonymous):
is the hole at 1 or -1?
OpenStudy (anonymous):
-1 @wio
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OpenStudy (anonymous):
Good. Now let \(x=0\) and find the \(y\) intercept.
OpenStudy (anonymous):
That will tell you what value it should be when it hits the y axis.
OpenStudy (anonymous):
2? @wio
OpenStudy (anonymous):
No
OpenStudy (anonymous):
or 1? @wio
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OpenStudy (anonymous):
show your work
OpenStudy (anonymous):
Is it 1?
OpenStudy (anonymous):
Are you trying to make me angry?
OpenStudy (anonymous):
Plug \(x=0\). What do you get?
OpenStudy (anonymous):
Excuse you? I am just asking ok?
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OpenStudy (anonymous):
I never did anything to disrespect you ok?
OpenStudy (anonymous):
Well, you are playing this guess and check game, even though I asked for you to show me your work.
OpenStudy (anonymous):
Ok but I am just asking and that happens! That is there people like you to help students like us to be able to solve it!
OpenStudy (anonymous):
wait just to be clear it would be 0-1=y right?
OpenStudy (anonymous):
no, we have \[
y = \frac{4x^2-4x-8}{2x+2}
\]
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
then we let \(x=0\)
OpenStudy (anonymous):
oh ok i apoligize!
OpenStudy (anonymous):
I wasn't being serious.
OpenStudy (anonymous):
oh ok! really, you did that to make me show the work! :)
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OpenStudy (anonymous):
i get -4!
OpenStudy (anonymous):
@wio
OpenStudy (anonymous):
Yeah. So we can now do elimination. We know there is a hole at \(x=-1\) and it goes through the \(y\) axis at \(y=-4\).
OpenStudy (anonymous):
yup!
OpenStudy (anonymous):
would it be the second answer @wio
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OpenStudy (anonymous):
but the second one has a hold at \(x=1\) so it can't be right.
OpenStudy (anonymous):
the third one @wio
OpenStudy (anonymous):
Guessing again?
OpenStudy (anonymous):
Does the third one go through \(y\) at \(-4\)?
OpenStudy (anonymous):
no the x=-1
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OpenStudy (anonymous):
nevermind its the 4th one? i have to be right!
OpenStudy (anonymous):
@wio
OpenStudy (anonymous):
right?
OpenStudy (anonymous):
@wio
OpenStudy (anonymous):
does the 4th one go through \(4\) when it intersects with \(y\) axis?
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OpenStudy (anonymous):
no?
OpenStudy (anonymous):
then the 4th one can't be right.
OpenStudy (anonymous):
its the first one! @wio
OpenStudy (anonymous):
Yes...
OpenStudy (anonymous):
ok i did the next one and i already eliminated the last two answers
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OpenStudy (anonymous):
@wio
OpenStudy (anonymous):
it already plugged in 0 and got the answer that it is -6
OpenStudy (anonymous):
@wio
OpenStudy (anonymous):
right? or at least @UsukiDoll can you help me out here
OpenStudy (anonymous):
hello @UsukiDoll
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OpenStudy (agent0smith):
^post a new question for a new question. More people see it. Question doesn't get messy.
OpenStudy (anonymous):
@UsukiDoll Can you help me out!