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Physics 17 Online
OpenStudy (anonymous):

anyone can help me solve pole vaulter's paradox?

OpenStudy (roadjester):

ok, one door or two doors?

OpenStudy (anonymous):

one door

OpenStudy (roadjester):

ah, that one is trickier this is gonna be FUN!

OpenStudy (anonymous):

pls help, I'm so confused now...

OpenStudy (roadjester):

do you need numbers? or will an explanation do?

OpenStudy (anonymous):

v=0.8c, pole=4m, barn=3m

OpenStudy (anonymous):

im stuck on the pole head reaches wall part..

OpenStudy (roadjester):

ok \[F={dp\over dt}\]

OpenStudy (anonymous):

wut....??? i don't get it..

OpenStudy (roadjester):

ok, so F = ma right? now classically p=mv so F=m dv/dt

OpenStudy (roadjester):

make sense

OpenStudy (anonymous):

then?

OpenStudy (roadjester):

so F=dp/dt now relativistically \[\huge \vec p = \gamma m \vec v\] so \[\huge \vec F = {d{(\gamma mv)} \over {dt}}\] Once you do the calculus \[\huge \vec F = {m\vec a\over \gamma ^3}\] You'll need this in a bit

OpenStudy (roadjester):

Now in the reference frame of the barn, through length contraction the pole will contract thus allowing it to fit right?

OpenStudy (roadjester):

In the reference frame of the pole, the barn ALSO CONTRACTS

OpenStudy (roadjester):

but here's the kicker. The pole collides with the wall

OpenStudy (anonymous):

i know that.. and the tail is not gonna stop immediately..

OpenStudy (roadjester):

so the pole will deform

OpenStudy (roadjester):

and since the force of impact can only travel down the length of the pole at the speed of light, the end of the pole doesn't know that the front has impact the wall

OpenStudy (roadjester):

Making sense?

OpenStudy (roadjester):

I've never actually performed the mathematical calculation but I know what it involves. So I can only kind of guide you.

OpenStudy (anonymous):

i think i need to see the actual calculation. but it's ok. thanks

OpenStudy (roadjester):

oww, my pride lol @ybarrap @raffle_snaffle

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