anyone can help me solve pole vaulter's paradox?
ok, one door or two doors?
one door
ah, that one is trickier this is gonna be FUN!
pls help, I'm so confused now...
do you need numbers? or will an explanation do?
v=0.8c, pole=4m, barn=3m
im stuck on the pole head reaches wall part..
ok \[F={dp\over dt}\]
wut....??? i don't get it..
ok, so F = ma right? now classically p=mv so F=m dv/dt
make sense
then?
so F=dp/dt now relativistically \[\huge \vec p = \gamma m \vec v\] so \[\huge \vec F = {d{(\gamma mv)} \over {dt}}\] Once you do the calculus \[\huge \vec F = {m\vec a\over \gamma ^3}\] You'll need this in a bit
Now in the reference frame of the barn, through length contraction the pole will contract thus allowing it to fit right?
In the reference frame of the pole, the barn ALSO CONTRACTS
but here's the kicker. The pole collides with the wall
i know that.. and the tail is not gonna stop immediately..
so the pole will deform
and since the force of impact can only travel down the length of the pole at the speed of light, the end of the pole doesn't know that the front has impact the wall
Making sense?
I've never actually performed the mathematical calculation but I know what it involves. So I can only kind of guide you.
i think i need to see the actual calculation. but it's ok. thanks
oww, my pride lol @ybarrap @raffle_snaffle
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