Sherry missed the lesson on normal distribution and needs to do her homework. Explain to Sherry how to use the mean and standard deviation of a normal distribution to determine the top 7% of the population. @ganeshie8
pls help??!
Let's see....
We want \[\Phi\left(\frac{x-\mu}{\sigma}\right) = 1-0.07=0.93\]
hmmm. whats the first symbol?
We'd solve for \(x\). Where as \(\mu\) is the man, and \(\sigma\) is standard deviation.
Hmm, well it finds cumulative distribution.
\(x\) would tell us the score that is at the boundary between the 93% and the 7%.
and then what will we do?
Actually "determine the top 7% of the population" is sort of vague. I interpreted it to mean the score at which you would be at the border. The question is not very precise.
eh i know but this is how it is word for word and its worth ten points
First, you use \[ z=\frac{x-\mu}{\sigma} \] to find the \(z\) score. \(\mu\) is mean and \(\sigma\) is standard deviation. Next, you would look up \(z\) in your \(z\) table.\[ P = \Phi(z) \]In this case \(P\) is what you find in the table, and it is the probability that your score is under \(x\).
With the current question, we have \(P\) is already provided. When looking at the top 7%, this is the opposite of being in the bottom 93%. So we let \(P = 0.93\). We do the \(z\) table look up, but instead of looking up \(z\), we find look to see what \(z\) value will give us \(0.93\).
then we can finally solve for \(x\).
so what do i plug in for x in the z score formula
We are trying to find \(x\).
im confused so thats the answer?
Okay, first of all, do you have a \(z\) table with you?
yess
Tell me what it says when \(z=0\).
.5000
How, try to find a \(z\) that will result you in getting \(0.97\)
I mean \(0.9300\)
ok hold on
I cant find that sorry
You will have to use the closest thing.
uhh ok 1.48
So our \(z\) score is \(1.48\). Do you know what the mean and std dev are?
\[ 1.48\approx \frac{x-\mu}{\sigma } \]
then? no i dont, can you expllain were we got our z score from pls?
Well, typically you learn the \(z\) score is just \[ z=\frac{x-\mu}{\sigma } \]This is just a normal fact. I could show you where it is from, but the truth is that it would probably confuse you more.
no like in the lessoon we learned thattt the only way to get z score is throught the deviation and first score minus the second but howd youu get it without everything because i have to expllain iit too
Well, I'm not sure then. I don't know what you are talking about.
pls :/ if you cant explain, then can you just give me the final answer with compllete sentences
It seems I can't really help out beyond what I have said.
no can you like give me the summary of the answer I wont have you explain it to me plss?
I don't know the answer.
:( do you know anybody that can help me?
@ranga
@eliassaab
@shamil98
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