chemistry

Question

chemistry

anonymous · Answer

What is the question?

anonymous · Answer

A solution is made by dissolving 3.8 moles of sodium chloride (NaCl) in 185 grams of water. If the molal boiling point constant for water (Kb) is 0.51 °C/m, what would be the boiling point of this solution? Show all of the work needed to solve this problem.

anonymous · Answer

molarity of NaCl solution = 3.8 mol / 0.185 kg = 20.54 molal. Since NaCl is ionic, the concentration of ions in the solution is 2X10.54 = 41.1 molal 

DTb = Kb m = 0.51C/m X 41.1 = 21 C 

So, the boiling point of the solution will be 100C + 21 C = 121 C.

anonymous · Answer

Thank you!!!

anonymous · Answer

No problem, you may want to check my math just to be sure though.

anonymous · Answer

can you help me with this one? ....

anonymous · Answer

A solution is made by dissolving 25.5 grams of glucose (C6H12O6) in 398 grams of water. What is the freezing-point depression of the solvent if the freezing point constant is -1.86 °C/m? Show all of the work needed to solve this problem.