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Mathematics 13 Online
OpenStudy (anonymous):

lim x->pi (1+cos^3x)/sin^2x (without L'hospital)

ganeshie8 (ganeshie8):

\(\large \lim \limits_{x \to \pi} \frac{1+\cos^3x}{\sin^2x} \) \(\large \lim \limits_{x \to \pi} \frac{\sin^2x + \cos^2x+\cos^3x}{\sin^2x} \) \(\large \lim \limits_{x \to \pi} \frac{\sin^2x }{\sin^2x} + \frac{\cos^2x+\cos^3x}{\sin^2x} \) \(\large \lim \limits_{x \to \pi} 1 + \frac{\cos^2x(1+\cos x)}{1-\cos^2x} \) \(\large \lim \limits_{x \to \pi} 1 + \frac{\cos^2x(1+\cos x)}{(1+\cos x)(1-\cos x)} \) \(\large \lim \limits_{x \to \pi} 1 + \frac{\cos^2x}{(1-\cos x)} \)

ganeshie8 (ganeshie8):

take the limit..

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