Question

how do you solve log base4 (x) + log base4 (x-12)=3

Answer 1

\[\log_{4} (x)+\log_{4} (x-12)=3 \]

Answer 2

log a*b = log a + log b
so
log a + log b = log ab
\[\log_{4} x +\log_{4} (x-12)=\log_{4} (x*(x-12)=3) \]

Answer 3

\[x*(x-12)=4^{3}=64\]

Answer 4

x^2-12x-64=0
(x-16)(x+4)=0
now do little bit by urself
@soccer106