Question

please help! how do you solve log base2 (x+1) - log base2 (x-4)=3

Answer 1

One thing: \[\log(a) - \log(b) = \log(a/b)\]

Answer 2

Also, log is not defined for a negative or zero. So keep that in mind.

Answer 3

\[\log_{2} \frac{ x+1 }{ x-4 }=3 \]

Answer 4

then do i put 2 to the third power?

Answer 5

Yes.

Answer 6

i got X= 4.7142 is that correct

Answer 7

Yeah.

Answer 8

ok thank u!!!!