Question

what is the equation of the normal to the curve y=x^2 at (2,3)

Answer 1

\[
y= x^2\\
y'= 2 x\\
y'(2)=4
\]
What is the slope of the normal?

Answer 2

4 is the slope of the tangent

Answer 3

-1/4 is the slope of the normal

Answer 4

(2,3)
\[
y-3 =-\frac 1 4(x-2)
\]
is the equation of the normal

Answer 5

\[
y =-\frac x 4+ \frac 12 +3\\
y =-\frac x 4+ \frac 72 \\
\]

Answer 6

Did you understand it?

Answer 7

seems @eliassaab provided the whole solution ::-P