Determine whether the relation shown in the table is a direct variation, an inverse variation, or neither. If it is a direct or inverse variation, write an equation for the function.

x: 10, 15, 20, 25
y: 1/2, 1/3, 1/4. 1/5

I'll give a medal to the person who helps! :) I've been stuck on this for a while. I know it's got something to do with 5 but I'm just too sleep deprived to wrap my head around it.

Question

Determine whether the relation shown in the table is a direct variation, an inverse variation, or neither. If it is a direct or inverse variation, write an equation for the function. 

x: 10, 15, 20, 25
y: 1/2, 1/3, 1/4. 1/5


I'll give a medal to the person who helps! :) I've been stuck on this for a while. I know it's got something to do with 5 but I'm just too sleep deprived to wrap my head around it.

anonymous · Answer

@satellite73 could you help me out? :)

anonymous · Answer

@sammixboo I need help!

anonymous · Answer

@ganeshie8 would you mind explaining this to me? running out of time :(

anonymous · Answer

I'm pretty sure it's inverse and y=5/x, am I correct?

ganeshie8 · Answer

Excellent !!!!!

ganeshie8 · Answer

good job :)

anonymous · Answer

thank you!! A lack of sleep has made everything far too complicated today lol. Could you assist me in this one? 
(z^2-4)/(z-3) divided by (z+2)/(z^2+z-12)

ganeshie8 · Answer

change the division into multiplicaiton 
by taking the reciprocal of second fraction

ganeshie8 · Answer

(z^2-4)/(z-3) divided by (z+2)/(z^2+z-12)

is same as 

(z^2-4)/(z-3)  *  (z^2+z-12)/(z+2)

ganeshie8 · Answer

next, factor the numerators, and see if u can cancel somethings

ganeshie8 · Answer

for factoring z^2-4, use difference of squares formula.
for factoring z^2+z-12, use any method u knw.. 

can u do it ha ? :)

anonymous · Answer

so it'd be (z+2)(z-2) for the first, I'm pretty sure, but the second one I'm not getting.

ganeshie8 · Answer

sorry i didnt get notification that u replied :|

ganeshie8 · Answer

u still need stuck on this one ?

ganeshie8 · Answer

@cobainxo

anonymous · Answer

Yeah I'm still stuck, I opened a new question for it. I'm slowly but surely getting there I think lol. This is what we've got so far: http://openstudy.com/study#/updates/53026905e4b018b5842499f9

ganeshie8 · Answer

above is the complete solution,
see if it looks okay... sorry for replying late...

anonymous · Answer

Thank you!! I appreciate it endlessly

ganeshie8 · Answer

wait a sec, let me correct a typo

anonymous · Answer

thank you again!!! would there be any restrictions on the variable?

ganeshie8 · Answer

(z^2-4)/(z-3)  *  (z^2+z-12)/(z+2)

(z+2)(z-2)/(z-3)  *  (z+4)(z-3)/(z+2)

 (z-2)(z+4)

ganeshie8 · Answer

yes !
restrictions are  :  3, -4, 3, -2

anonymous · Answer

Alright. Thank you again, you're a life saver.

ganeshie8 · Answer

np... u wlc :)