Find the zeros of the function. state any multiplicities. f(x)=x^4-4x^3+3x^2

Question

campbell_st · Answer

there is a common factor of x^2

so you have 

$$f(x) = x^2(x^2 - 4x + 3)$$

now factor the quadratic... 

the zero x = 0  has a multiplicity of 2, all others have a multiplicity of 1.

anonymous · Answer

here are my answer choices
A.{-3(multiplicity 2 ), -1( multiplicty 2), 0 }
B. {0 ( multiplicity 2), 1,2,3
C. {0 ( multiplicity 2), 1 ( multiplicity 2),3 }
D. { -3,-1,0 ( multiplicity 2) }

campbell_st · Answer

well you know x = 0 has a multiplicity of 2... 

what did you get when you factored the quadratic...?

the degree of the polynomial is 4... so the multiplicities of the roots need to equal 4... 

so some of your choices can be eliminated

anonymous · Answer

Like A and D