]In a lab, a student dissolves 6.9 g of sodium chloride (NaCl) in 125 g of water (H2O). What is the molality concentration of the solution?
Molartiy = Moles/Litres
Density of water is 1g/mL
you can mostly assume that 1g = 1mL of water but different temperatures and pressures can change this relationship
So how would I find the answer out? The answer choices are: 9.4 x 10-4 m 0.055 m 0.94 m 18.0 m
Read what I wrote
Moles = Grams/Molecular Mass
sorry forgot that formula
So you need to convert your grams of sodium chloride to moles
and convert your grams of water to litres of water
You know how to find molecular mass right?
So I would do 6.9g of sodium chloride divided by the mass of sodium chloride?
the molecular mass of sodium chloride (which has units g/mol)
So wait, would it just be the mass of Na and Cl and then add the two?
If I wanted to find the molecular mass of Hydrogen gas (H2) I would look at the periodic table and find, One hydrogen atom has a molecular mass of 1.00794g/mol Thus, H2 gas has a molecular mass of 1.00794g/mol + 1.00794g/mol = 2.01588g/mol Then I would just take the grams of H2 gas I had and divide it by the number I just calculated to find the moles of H2 gas I had
yes
Because if so then it would be 6.9 divided by 58.44 which is .12 then what do I do?
Opps forgive me
make sure to include units in your calculations
So you have 0.12moles Now you need to convert the grams of water to litres of water
then use the molarity formula
Which would be 125 litres, right?
Read what I wrote above
1g= 1ml, so what would one ml be to one L?
1000 mL = 1L
This is stuff you need to memorize
If you plan on going on into sciences/engineering in post secondary
Just to note.
Well I was suppose to learn it in my chem class, but my teacher wasn't good so this is why I am in online school for chem
Its fine man just work hard you will get this stuff it is actually pretty simple, and you seem smart
https://www.youtube.com/watch?v=ScvuRb6vsz4 this might help with unit conversion
So it would be .125 so would I do .12 divided by .125 for the final answer?
yes
So it would be around .96 so I would go with .94 for the answer?
Also do you think you would have time to help me with like two other questions??
Maybe if they are quick I have a lot of stuff to do
What is the pressure, in mm Hg, of 2.50 moles of an ideal gas if it has a volume of 50.0 liters when the temperature is 27.0° C?
and A sample of gas has a volume of 20.0 liters at 22.0° C. If the pressure remains constant, what is the volume at 100.0° C?
PV=nRT Ideal Gas law wikipedia it
The second one also uses Ideal gas law
So for the second one these are the answer choices: 15.8 liters 24.4 liters 25.3 liters 90.1 liters Would it be the 3rd one???
Which means? Lol I am sorry that made no sense.
Look up idea gas law on wikipedia it tells you all the variables in the equation
You need to use it when dealing with gasses, though remember it models gasses thats constituents do not interact with each other
So it is not a real model it just simplifies things, because in reality (a real gas) the atoms/molecules that make it up interact with eachother
But that is just a side note about the law that you should know
Like, \[P = n_1R_1T_1\] \[P = n_2R_2T_2\] Where the first equation is for the first state of the gas and the second denotes the second state of the gas Temperature and volume are proportional Temperature and pressure are inversely proportional (This makes sense if you think about it, remember temperature is just kinetic movement of particles (atoms/molecules)) So since pressure is constant, P will remain the same in both equations (because it is constant or unchanging in the process of this question)
Opps! There should be a V in those equations
\[P = \frac{n_1T_1R}{V_1}\] \[P = \frac{n_2T_2R}{V_2}\]
you can set these two equations equal to each other, and cancel out the constants. number of moles do not change so they cancel, R is always a constant so it cancels
Do you follow?
I am trying to do the first one and I am so confused on it
So for the first one "What is the pressure, in mm Hg, of 2.50 moles of an ideal gas if it has a volume of 50.0 liters when the temperature is 27.0° C?" n=2.5 moles T=27 and R would be equal to what?
R is the ideal gas constant
You need to use the one with the correct units
or else you will get the wrong answer
Unit conversion is very important in these questions, you need to realize when you divide two units they cancel out, for instance, 1mL/1mL = 1 (units canceled, scaler quantity now) 1mL*1g = 1g*mL 1L/2mL = 0.5L/mL 2L*g/1g = 2L
So which do I use for the first one???
Look at your units
If the units dont cancel out when you write out the equation then you are using the wrong gas constant
You should be left with units for the variable you are solving
Right now have is 2.5 moles times 27(temp) times R(?) divided by 50(Liters)
Also, if you have Celsius you need to convert to Kelvin
273 + Celsius = Kelvin
OHHHHHHHHHHHHHH!!
kelvin has the units K and is the Metric unit for temperature
I forgot to mention
Okay let me see if I know the answer now
Ok I will be back in probably 20-30 minutes I need to see if the patch on my cars tire is actually going to hold.
Okay
Back did you figure it out? Sorry for taking so long tire is working but needed to re-setup sound system so blah smeh
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