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Calculus1
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Convert the polar equations r=6 Cos 4 θ
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multiply both sides wid \(r\)
\(r^2 = 6r\cos 4\theta \)
\(x = r\cos 4\theta\) \(y = r\sin 4\theta\) \(r^2 = x^2 + y^2\)
the equation becomes : \(x^2 + y^2 = 6x\)
Thank u
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np :)
ive got second thoughts on this
looks i messed it up, @ikram002p help plz
@Diana97 i think we cannot simpify like that.
the answer wud be : \(x^2 + y^2 = 6\cos (4*\tan^{-1}(y/x))\)
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it wont simplify i believe.
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