Question

A bird (B) is spotted flying 900 feet from an observer. The observer (O) also spots the top of a tower (T) at a height of 200 feet. What is the angle of depression from the bird (B) to the observer (O)?

Right triangle OTB is shown. Side OT labeled 200 and side BO is labeled 900. The angle B is labeled x degrees.

12.52°

12.84°

77.16°

83.69°

Answer 1

@radar

Answer 2

sin x = 200/900, I don't know what to do after this.

Answer 3

\[x=\frac{180 \sin ^{-1}\left(\frac{200}{900}\right)}{\pi }=12.8396 \]
12.84 degrees.

Answer 4

sin^-1 is the ArcSin function.

Answer 5

Thanks, that makes sense. Could you help me with one more?

Answer 6

I can try.

Answer 7

Make new thread or ok on this one?

Answer 8

Go ahead on this one.

Answer 9

An observer (O) spots a plane (P) taking off from a local airport and flying at a 33° angle horizontal to her line of sight and located directly above a tower (T). The observer also notices a bird (B) circling directly above her. If the distance from the plane(P) to the tower (T) is 7,000 ft., how far is the bird (B) from the plane (P)?

A diagram is shown with two parallel lines cut by a transversal. One angle is marked 33 degrees, one side is marked 7000 and another side is marked x.

3815 feet

5873 feet

8343 feet

10,779 feet

Answer 10

I thought I had figured it out and got 3815 but that was wrong.

Answer 11

From the illustration, the length of x is equal to OT.
OT=7000 * Cot[ 33 degrees]
or
10779.1
according to Mathematica.

Answer 12

Thanks so much, i've been working on this half the day because I keep getting questions wrong. Now I got a 100! I'll fan you and give best response.

Answer 13

Well it is always nice to get a 100.
Congratulations.

Answer 14

Thanks again, I'll close the question now.