If x varies inversely with y and x = 8 when y = 10, find y when x = 6.
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OpenStudy (anonymous):
y=7.5?
OpenStudy (anonymous):
y = k/x, where k is a constant
given y = 10 and x = 8. Use them to solve for k, then use the equation to solve for y when x = 6
OpenStudy (whpalmer4):
Inverse variation of x and y implies \[y = \frac{k}{x}\] with \(k\) being the constant of variation. Plug in \(x=8, y=10\) and solve for \(k\). Use that value of \(k\) with \(x=6\) to find \(y\)
OpenStudy (anonymous):
\[10=k/8 \]
OpenStudy (whpalmer4):
Good, keep going...\(k=\)?
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OpenStudy (anonymous):
10*k=8?
OpenStudy (whpalmer4):
\[10=\frac{k}{8}\]You want \(k\) all by itself, so multiply both sides by \(8\):
\[8*10 = \cancel{8}*\frac{k}{\cancel{8}}\]\[k=\]
OpenStudy (anonymous):
80
OpenStudy (whpalmer4):
Good, so the equation is \[y = \frac{80}{x}\]What does \(y=\) when \(x = 6\)?
OpenStudy (anonymous):
13.3333?
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OpenStudy (anonymous):
So 40/3 is the answer
OpenStudy (anonymous):
Thx @whpalmer4
OpenStudy (whpalmer4):
Yes, it is, and for playing "solve that problem" today, we have a nice commemorative graph for your viewing pleasure!