Question

Factor the following quadratic 4x^3-x^2-4x+1

Answer 1

this is cubic not quadratic

Answer 2

well its on my quadratics quiz so...

Answer 3

My homework is to factor things out too lol :D

Answer 4

I just need help :(

Answer 5

Me too :D

Answer 6

im not sure how to do this correctly

Answer 7

4x^3-x^2-4x+1

put x=1, get
4(1)^3-(1)^2-4(1)+1 = 4 - 1 - 4 + 1 = 0
it means (x-1) is one of the factor of 4x^3-x^2-4x+1. then you can find the other factors by using long division or by using Horner

Answer 8

k thanks

Answer 9

(x^2-1)(4x-1), but you can factor further to (4x-1)(x+1)(x-1)

Answer 10

yeah, that's full factor for it. but it would be nice if you can show your steps (not only answer) @Nanalew

Answer 11

im not so sure how you got that but thanks

Answer 12

Okay then, trying to factor by pulling out so split the expression into two groups: Group 1: -x2+1
Group 2: 4x3-4x
Pull out from each group separately :

Group 1: (-x2+1) • (1) = (x2-1) • (-1)
Group 2: (x2-1) • (4x)
Add up: (x^2-1)(4x-1)

Then factor (x^2-1)
Check : 1 is the square of 1
Check : x2 is the square of x1
Factorization is :
(x + 1) • (x - 1)
Then
(4x - 1) • (x + 1) • (x - 1)

Answer 13

Heres the work @RadEn, sorry should have posted before answer :)

Answer 14

ok, nope. better late than never :)