Question

ya'll ready for this?
precal, parabolas, foci, directrix, vertex etc...
solve: x^2=64

Answer 1

Okay, did you read your text book?

Answer 2

why? I have notes, does that count?

Answer 3

Well, do you know what the foci, directrix, and vertex are?

Answer 4

Where are you stuck?
It looks like you just want us to solve it for you and explain everything.

Answer 5

This equation isn't even a parabola. It's a line.

Answer 6

yes, i have to graph them and stuff. Well, I would like to understand how to solve the equation and graph. And omg... you're right... *facepalm*

Answer 7

i don't know where to start wio, do I square root the 64 to get x=8?

Answer 8

Well, square root give us \[
|x| = 8
\]And this means \(x=8\) and \(x=-8\). We have two parallel lines.

Answer 9

my teacher wants us to graph this... -_-

Answer 10

wait a minute, i think should ask you a parabola instead or something else.

Answer 11

well yeah, but may i ask a different one now that i realize how simple that was.

Answer 12

Wait that wasnt the question lol it was x^2=6y

Answer 13

@iambatman Can you do this?

Answer 14

x^2=6y?

Answer 15

yes

Answer 16

So what do you need to know about it lol

Answer 17

i have to solve the equation and graph it. its in the conic section of precalculus

Answer 18

Well what can you tell me about the shape :p

Answer 19

can you help me? do you know how to do it?

Answer 20

Yes, I believe so, it's a parabola.

Answer 21

A parabola is the set of all points at an equal distance from a fixed point and a fixed line.

horizontal (y term is square)

\[(y-k)^2=4p(x-h)\]

vertical (x term is squared)

\[(x-h)^2 = 4p(y-k)\]

vertex \[(h,k)\]

Answer 22

Also p = distance and direction from vertex to focus, distance and opposite direction from vertex to directrix.

Answer 23

This is what you pretty much need to know, to solve this problem.

Answer 24

So first thing, what kind of sketch would we get, horizontal or vertical?

Answer 25

yeah i know about the two equations and everything. But by looking at this equation tell me how do i know if its vertical or horizontal?

Answer 26

Look at what I wrote above each of the equation.

Answer 27

ohhhhhhhhhhhhhh omg i gooooooooooooooooooooooottttt ittt!!!!!

Answer 28

:)

Answer 29

@wio was this explanation good enough? :P

Answer 30

im not done tho

Answer 31

What do you need to know now?

Answer 32

lol, how do you use the equation?

Answer 33

awww man now what do i do...

Answer 34

wio what are you doing?

Answer 35

What's the vertex?

Answer 36

0,0

Answer 37

am i wrong?

Answer 38

I think we need to use \[
x^2=4py
\]

Answer 39

\[
6y=4py \implies \frac32=p
\]

Answer 40

This means the focus is at \((0,3/2)\)

Answer 41

The directrix is the line \(y=-3/2\)

Answer 42

Vertex is (0,0)

Answer 43

Yes, that's all of it, right?

Answer 44

Yup

Answer 45

Should be able to graph it now :P

Answer 46

I'm somehow not in the mood today. Thanks for helping out.

Answer 47

No worries :P

Answer 48

uh, thank you... um, you deserve a medal...

Answer 49

I'm to lazy to draw the graph since I'm a bit busy right now, I'll just show you a little sample how it should look... It's not precise but it should help you out! Good luck!