Question

Solve:
3((sec^2)x)-4 =0

Answer 1

\[3\sec ^{2}x-4=0\] This is a better view of the equation.

Answer 2

\[\sec^2(x)=\frac{4}{3}\] is a start, so
\[\cos^2(x)=\frac{3}{4}\]

Answer 3

that makes
\[\cos(x)=\pm\frac{\sqrt3}{2}\] and now you are mostly done, so long as you know a number whose cosine is \(\frac{\sqrt3}{2}\) and another number whose cosine is \(-\frac{\sqrt3}{2}\)

Answer 4

How do you know if it is in quadrant I, II, III, or IV?

Answer 5

cosine is like x. If it is positive, it is in quadrant I, or IV
If it is negative, it is in quadrant II or III

Answer 6

So if your domain is 0 to 360, there should be 4 answers...1 in each quadrant.