Mathematics
7 Online
OpenStudy (anonymous):
Medal given! Please help with 3.a, b,c and 4 a,b,c,d
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
OpenStudy (anonymous):
\[256^x=\frac{1}{16}\]?
OpenStudy (anonymous):
I'm guessing we would have to do the inverse?
OpenStudy (anonymous):
\(256=16^2\)
OpenStudy (anonymous):
so
\[256^x=(16^2)^x=16^{2x}\]
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
your equation is now
\[16^{2x}=\frac{1}{16}\] or
\[16^{2x}=16^{-1}\] making
\[2x=-1\]
OpenStudy (anonymous):
and then solving for x we would divide both sides by 2 so x=-1/2?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
ok :)) so for a i'd need to raise both x and 3 to the 3rd power?
OpenStudy (anonymous):
\[(x-3)^3=64\]take the cubed root of both sides
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
on no no, \((x-3)^2\neq x^2-3^3\) you don't want to do that at all
do you know what the cubed root of \(64\) is?
OpenStudy (anonymous):
no is a fine answer, i am just asking if you know it
if not, i will tell you
OpenStudy (anonymous):
i'm not sure off the top of my head..
OpenStudy (anonymous):
ok it is 4, and the reason we would know it is because \(4^3=4\times 4\times 4=16\times 4=64\)
OpenStudy (anonymous):
so if \((x-3)^3=64\) then you know \(x-3=4\)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so to find x you would basically at 3 on both sides of the equal sign to find x?
OpenStudy (anonymous):
add*
OpenStudy (anonymous):
x=7
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
oh ok :-) thank you
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yw
OpenStudy (anonymous):
and for c it's just simply raising the 1/5 reciprocal?
OpenStudy (anonymous):
for c it is
\[x=\sqrt[5]{32}^4\]
OpenStudy (anonymous):
do you know that the fifth root of 32 is?
OpenStudy (anonymous):
not quite sure
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
actually yes i do! :) it's 2^5=32
OpenStudy (anonymous):
tada!
OpenStudy (anonymous):
so \(\sqrt[5]{32}=2\)
your last job it to find \(2^4\)
OpenStudy (anonymous):
which is 8
OpenStudy (anonymous):
nope
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
\(2^3=8\)
OpenStudy (anonymous):
16
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
yay!
OpenStudy (anonymous):
yay indeed!
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Thank you so much.. you really helped me a lot :)
OpenStudy (anonymous):
If you don't mind I wanted to ask you really quick if there is a specific method to do 4 a-d
OpenStudy (anonymous):
@satellite73
OpenStudy (anonymous):
sure
OpenStudy (anonymous):
for a, count from the places you have to move to the left to get from \(37,000,000\) to the decimal in \(3.7\)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i count seven places, making
\[37,000,000=3.7\times 10^7\]
OpenStudy (anonymous):
oh ok :) thanks so much!!
OpenStudy (anonymous):
are the rest ok?
OpenStudy (anonymous):
in b you have to count to the left 4 places, making
\[0.000801=8.01\times 10^{-4}\]
OpenStudy (anonymous):
sorry, i meant count to the right
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
yw