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Mathematics 7 Online
OpenStudy (anonymous):

Medal given! Please help with 3.a, b,c and 4 a,b,c,d

OpenStudy (anonymous):

OpenStudy (anonymous):

\[256^x=\frac{1}{16}\]?

OpenStudy (anonymous):

I'm guessing we would have to do the inverse?

OpenStudy (anonymous):

\(256=16^2\)

OpenStudy (anonymous):

so \[256^x=(16^2)^x=16^{2x}\]

OpenStudy (anonymous):

your equation is now \[16^{2x}=\frac{1}{16}\] or \[16^{2x}=16^{-1}\] making \[2x=-1\]

OpenStudy (anonymous):

and then solving for x we would divide both sides by 2 so x=-1/2?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok :)) so for a i'd need to raise both x and 3 to the 3rd power?

OpenStudy (anonymous):

\[(x-3)^3=64\]take the cubed root of both sides

OpenStudy (anonymous):

on no no, \((x-3)^2\neq x^2-3^3\) you don't want to do that at all do you know what the cubed root of \(64\) is?

OpenStudy (anonymous):

no is a fine answer, i am just asking if you know it if not, i will tell you

OpenStudy (anonymous):

i'm not sure off the top of my head..

OpenStudy (anonymous):

ok it is 4, and the reason we would know it is because \(4^3=4\times 4\times 4=16\times 4=64\)

OpenStudy (anonymous):

so if \((x-3)^3=64\) then you know \(x-3=4\)

OpenStudy (anonymous):

so to find x you would basically at 3 on both sides of the equal sign to find x?

OpenStudy (anonymous):

add*

OpenStudy (anonymous):

x=7

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

oh ok :-) thank you

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

and for c it's just simply raising the 1/5 reciprocal?

OpenStudy (anonymous):

for c it is \[x=\sqrt[5]{32}^4\]

OpenStudy (anonymous):

do you know that the fifth root of 32 is?

OpenStudy (anonymous):

not quite sure

OpenStudy (anonymous):

actually yes i do! :) it's 2^5=32

OpenStudy (anonymous):

tada!

OpenStudy (anonymous):

so \(\sqrt[5]{32}=2\) your last job it to find \(2^4\)

OpenStudy (anonymous):

which is 8

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

\(2^3=8\)

OpenStudy (anonymous):

16

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

yay!

OpenStudy (anonymous):

yay indeed!

OpenStudy (anonymous):

Thank you so much.. you really helped me a lot :)

OpenStudy (anonymous):

If you don't mind I wanted to ask you really quick if there is a specific method to do 4 a-d

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

sure

OpenStudy (anonymous):

for a, count from the places you have to move to the left to get from \(37,000,000\) to the decimal in \(3.7\)

OpenStudy (anonymous):

i count seven places, making \[37,000,000=3.7\times 10^7\]

OpenStudy (anonymous):

oh ok :) thanks so much!!

OpenStudy (anonymous):

are the rest ok?

OpenStudy (anonymous):

in b you have to count to the left 4 places, making \[0.000801=8.01\times 10^{-4}\]

OpenStudy (anonymous):

sorry, i meant count to the right

OpenStudy (anonymous):

yw

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