Find an equation of the tangent line to the curve at the given point.
y=x^4+2x^2-x, (1,2)

Question

Find an equation of the tangent line to the curve at the given point. 
y=x^4+2x^2-x, (1,2)

dumbcow · Answer

here a good way of looking at tangent line
given f(x) and point (x1,y1)

$$y - y_1 = f'(x_1)(x - x_1)$$

whpalmer4 · Answer

Take the first derivative to get a function for the slope of the tangent line at a point.  Then use the value of the first derivative at the point to get the slope, and find the equation of the tangent line with the point-slope formula
$$y-y_0 = m(x-x_0)$$

anonymous · Answer

Thanks!

whpalmer4 · Answer

Should look like this when you're all done. What did you get for your answer?

anonymous · Answer

Yup, looks something similar!