Question

What is the average kinetic energy of a gas at 285 Kelvin? (R = 8.314 J/K-mol)

2.37 x 103 J/mol
7.11 x 103 J/mol
3.55 x 103 J/mol
1.77 x 103 J/mol

Answer 1

\[T= 2/3k <1/2mv ^{2}>\]
using above equation
\[T=2/3k<K.E> \]
\[<K.E> = 3kT/2\]
T = 285 Kelvin
k = 1.38 x 10^-23 JK^-1