Question

Find the derivative of the function defined as follows:
y= -8e^tanx

Answer 1

do you know chain rule ??

Answer 2

mhm

Answer 3

so what answer did you get for that ?

Answer 4

\(\Large y'= (-8e^{\tan x})' = -8 (e^{\tan x})(\tan x)' = ...\)

Answer 5

sooo... e^tanx = sin(x)/cos(x)^2 right?

Answer 6

Nope.

Answer 7

there is no need to convert tan to sin/cos here

do you know the derivative of tan x ??

Answer 8

ohhh. okay

Answer 9

it's (sec x) ^2 right?

Answer 10

Yes.

Answer 11

so, whats your answer ?

Answer 12

so is it -16(sec x)(e^tanx) ?

Answer 13

\(\Large y'= (-8e^{\tan x})' = -8 (e^{\tan x})(\tan x)' = -8 (e^{\tan x}) \sec^2 x
\)