Question

Using complete sentences, explain how you would factor completely x^9 – 64.

Answer 1

x^2-b^2 = (x-b)(x+b)

Answer 2

but that's an odd number for the x^9 part

Answer 3

(x^4.5-8)(x^4.5+8)

Answer 4

maybe perfect cubes?!

Answer 5

(x^(9/2)-8)((x^(9/2)+8)

Answer 6

It's a difference of two cubes. Use (a-b)(a^2+ab+b^2).

Answer 7

see ^^

Answer 8

u can continue to factor the negative parts

Answer 9

and use complex factors on the positive parts

Answer 10

where the heck.... why fractions on exponents the heck?!

Answer 11

HAHAHAHahaa

Answer 12

it works

Answer 13

It's still a difference of two cubes, and that's how you're intended to factor it initially.

x^9-64
a^3=(x^3)^3
b^3=(8)^3

Answer 14

tom and I win!

Answer 15

Difference of two cubes as in a^3-b^3, of course

Answer 16

tomhue 64=8^2

Answer 17

wait.. cube root of 64 is 4 right? since 4 x 4 = 16 x 4 =64?

Answer 18

64=4*4*4

Answer 19

Lol sorry, silly mistake. b=4