Question

I feel like I've been through this one already yet I'm still unsure of myself attempting to solve... Step by step help please?

http://awesomescreenshot.com/0632dd9n16

Answer 1

First step : convert the 'complex division problem' into 'multiplication problem' by flipping the bottom fraction

Answer 2

Is cross multiplication in this? or are we factoring...

Answer 3

factor the bottom y^2+y-6

Answer 4

\(\large \frac{\frac{y-1}{y^2+y-6} }{\frac{y-6}{y+3} } \)

\(\large \frac{y-1}{y^2+y-6} \times \frac{y+3}{y-6}\)

Answer 5

deleted previous reply, as it was hinting cross multiplicaiton...

Answer 6

there is no cross-multiplication involved here.
we oly need to factor, and cancel watever we can..

Answer 7

\[\frac{ y-1 }{ (y - 2 )(y + 3) } = \frac{ y + 3 }{ y - 6 }\]
I think my signs are right this time o.o

Answer 8

I ended up with
\[\frac{ (y-1)(y-6) }{ (y+3)^2 (y-2) }\]

Answer 9

\(\large \frac{\frac{y-1}{y^2+y-6} }{\frac{y-6}{y+3} } \)


\(\large \frac{y-1}{y^2+y-6} \times \frac{y+3}{y-6}\)


\(\large \frac{y-1}{(y+3)(y-2)} \times \frac{y+3}{y-6}\)


\(\large \frac{y-1}{(y-2)(y-6)}\)

Answer 10

you should end up wid above ^

Answer 11

Awe... they canceled each out didn't they ;-; I think it will finally stick with my head now. Thank you... I've improved tremendously with the concept of factoring with your help. Thank you!

Answer 12

glad to hear ! you wlcme =)