Can someone help me calculate the superior limit and the inferior limit of the sequence, given that the nth term is given by
A_n= (((-1)^n)*n)/(n+1) where n is superior or equal to 1

Question

Can someone help me calculate the superior limit and the inferior limit of the sequence, given that the nth term is given by 
A_n= (((-1)^n)*n)/(n+1) where n is superior or equal to 1

amistre64 · Answer

the ratio An/A(n-1) should be of use

amistre64 · Answer

(-1)^n  n /(n+1)
-------------------
(-1)^(n-1) (n-1)/(n)


    n /(n+1)
-------------------
(-1)^(n) (n-1)/(n)


  n^2 /(n+1)
-------------
(-1)^(n) (n-1)


(-1)^(n)  n^2 
-------------
  (n-1)(n+1)


(-1)^(n)  n^2 
-------------
    n^2 - 1

amistre64 · Answer

as n grows towards infinity, this approches -1, or 1 as the bounded limitations

anonymous · Answer

Could it have worked if i had seperated the equation as such ? 
(-1)^n          n
------- x   ------
n+1              n+1 
?

amistre64 · Answer

no, since multiplying fraction is not the same as adding them ....

anonymous · Answer

Oh wow .. That was a dumb mistake in my part sorry :S

amistre64 · Answer

:) 'sok

anonymous · Answer

But I understand your explanations .. Thanks Again :D

amistre64 · Answer

good luck