Use the triangle at the right. Find the length of the missing side. 1. a = 16, b = 63 2. b = 2.1, c = 2.9
|dw:1392747972117:dw|
Since this is a right triangle, the Pythagorean theorem applies, which states: \[a^{2} + b^{2} = c^{2}\] So, for the first problem: \[c = \sqrt{16^{2} + 63^{2}}\]
1.79 2.5
Ok so what'sthe second one?
how did you get the first one? can you show me?
10
The second problem is slightly more complicated. Rewrite the equation so that "a" is on the left side by itself: \[a^{2} = c^{2} - b^{2}\] Then take the square root of both sides: \[a = \sqrt{ c^{2} - b^{2}}\] Now insert the values for "b" and "c" that you were given: \[a = \sqrt{ (2.9)^{2} - (2.1)^{2}}\]
I apologize for skipping steps in the first problem. Here are all of the steps for soling the first problem. \[a^{2} + b^{2} = c^{2}\] Moving "c" to the left side of the equation: \[c^{2} = a^{2} + b^{2}\] Squaring both sides: \[c = \sqrt{a^{2} + b^{2}}\] Substituting the given values: \[c = \sqrt{16^{2} + 63^{2}}\] Hope this helps.
Just noticed there is one more step I made implicitly. The following are true: \[\sqrt{a^{2}} = a\] \[\sqrt{c^{2}} = c\]
Join our real-time social learning platform and learn together with your friends!