Find the normal line equations of slope 2 to the ellipse x^2 +2y^2 =3
hint : if the normal at a point has slope of 2, then tangent at that point will have a slope of -1/2
take the derivative, set it equal to -1/2 and u wil get a relation between y and x
aaah! I equated it to 2 instead of -1/2.
why is it equated to -1/2 instead of 2? This is a bit confusing for me
if the question was asking about TANGENT line, then u should be equating it to 2
but the question is asking about NORMAL line equations...
here is the relation : slope of tangent line = -1/(slope of normal line)
But you said that the slope of the tangent is -1/2 and the slope of the normal line is 2. So if I'm looking for the tangent line equation, shouldn't I be equating it to -1/2? And normal line equation to 2?
good question :) we already knw the slope of normal = 2
here we're oly trying to find a POINT, at which slope of normal equals 2.
it occurs when the tangent has a slope of -1/2
so take the derivative and set it equal to -1/2
if that makes any sense... :)
On the other hand, setting the derivative equal to 2, gives u the points at which TANGENT line has slope of 2. NOT THE NORMAL LINE ok ?
GOT IT! THANK YOU SO MUCH!!
np :)
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