Question

A balloon has a volume of 10,500 liters, and the temperature is 15°C. If the temperature were -25°C, what would the volume of the balloon be?

12,194 L
9,042 L

Answer 1

\[\frac{ V1 }{V 2 }=\frac{ T1 }{T2 }\]
T1=15+173=288 K
T2=-25+273=248 K
V1=10500 L
Calculate V2

Answer 2

12,194 L Is the right answer then! thanks Surjithayer :)

Answer 3

i think you have calculated wrong,lower the temperature less the volume.
\[\frac{ 10500 }{V2 }=\frac{ 288 }{248 },V2=\frac{ 248 }{288 }\times 10500 =?\]

Answer 4

Oh.. yeah you are right. Dang it lol oh well