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I'm trying to figure out a simple algebraic rearrangement, but I just can't get my head around it. One moment.
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\[\frac{ 1 }{ 1 + \frac{ 3 }{ \sqrt{13} }} = ?\] I can't find the original solution (It's lost forever), but it had two terms in the numerator being added, involved a 13, a sqrt(13), and a 4.
Pardon, that is supposed to be a minus sign in the denominator
\[\frac{1}{1-\frac{3}{\sqrt{13}}}\]Is that it?
I would start by multiplying by the fraction \[\frac{1+\frac{3}{\sqrt{13}}}{1+\frac{3}{\sqrt{13}}}\]
that will give you \[\frac{1+\frac{3}{\sqrt{13}}}{1-\frac{9}{13}}\]
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pI can't respond fully at the moment, but I see it; thanks. \derp
|dw:1392767854147:dw|
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