Question

So what is the the number of grams of excess regent left? In problem C3H8 +5O2=3CO2+H2O

Answer 1

find out how much you used and subtract that from what you had initially.

Answer 2

What info are you given?

Answer 3

If you start with 14.8g of C3H8 and 3.44g of o2

Answer 4

First, find the number of moles of both those substances.

Answer 5

Ok

Answer 6

I got 53.8 g O2

Answer 7

And for C3H8?

Answer 8

I'm sorry mole

Answer 9

Wait how did you do that? It's not right. Number of moles is mass/molar mass

Answer 10

0.0645mole CO2

Answer 11

Whoa wait back up. You have to look for the number of moles of C3H8 and O2 because those two are the only ones you have the mass to.

Answer 12

Yea

Answer 13

Number of moles is mass over molar mass. Please look at what you did and try again.

Answer 14

Ok

Answer 15

So I. Did 14.8 C3H8 x 1 mol c3h8/44gc3h8x5mol o2/ 1mol c3h8 x 1 mol 02 / 32g = 53.8g o2

Answer 16

Why do you multiply the moles for C3H8 with moles for O2? I am so confused. Do this:
for C3H8: 14.8/(36+8)
for O2: 3.44/(32)

Answer 17

Ok

Answer 18

By the way it was how I was taught in school

Answer 19

Do you want to wait for someone who may know the same method? I don't think I can work that.

Answer 20

why would u combine the c3h8 and o2 when calculating mols? those are 2 different compounds. if ur looking for excess reagent u have to look for limiting reagent i think

Answer 21

Yea

Answer 22

btw is ur equation given like that or u have to balance it urself?