Using the 8 balls, numbered from 1 to 8 from Question 1,) show that it is possible to make 6,720 different 5-digit numbers, using each number only once, (hint: The 'box' method may help you with this.)

(this step is if we DON'T need every 'thing; - if we only want to arrange some of them.)

Question

Using the 8 balls, numbered from 1 to 8 from Question 1,) show that it is possible to make 6,720 different 5-digit numbers, using each number only once, (hint: The 'box' method may help you with this.)

(this step is if we DON'T need every 'thing; - if we only want to arrange some of them.)

anonymous · Answer

http://openstudy.com/users/tl9800#/updates/530324dae4b024fe26e31150 This was question 1

anonymous · Answer

I am not supposed to use factorial for this one.

anonymous · Answer

oh

anonymous · Answer

okay

anonymous · Answer

I think it has to be the box method

anonymous · Answer

well then
# of selections for the first digit = n = 8
# of selections for the second digit = n-1 =7
.
.
.
# of selections for the fifth digit = n-4 =4

# of ways = 8*7*6*5*4=6720

anonymous · Answer

I'm not sure what box-method is. I tried googling.

anonymous · Answer

Thank you! I am pretty sure this is it!