Find the length of c if angle A=62 degrees angle B=39 degrees and b = 15.
draw a triangle so you can figure out what you are trying to find hard just with numbers and no picture
you got one?
drawing it :)
ok, draw it here then we can do it
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thats about what it looks like and this is trig that im working on aswell
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you want to use the law of sines \[\frac{a}{\sin(A)}=\frac{b}{\sin(B)}=\frac{c}{\sin(C)}\] you know \(A, b, B\) but you don't know \(C\) except you do what is \(C\) ?
i have no idea but yes its law of sines
of course you do
i meant \(A=62,B=39,C=?\)
if it is not clear, i will tell you
79
whew
thats right because triangles =180 degrees :)
so \[\frac{15}{\sin(39)}=\frac{c}{\sin(79)}\]
you have 3 out of the 4 numbers, you can find the fourth \[c=\frac{15\sin(39)}{\sin(79)}\] and a calculator
14.457/ -0.444
correct?
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