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integrate[sin^2(x)cos^4(x)]
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Even powers? oo this one is going to be a doozy!
You can use the `Half-Angle Identities` a bunch of times. Or another method is to use the `Reduction Formula`. Are you familiar with the Cosine Reduction Formula? It's really convenient.
the half angle yes, what's the cosine reduction formula?
\[\Large\bf\sf \int\limits \cos^n x\;dx \quad=\quad \frac{1}{n}\cos^{n-1}x \sin x+\frac{n-1}{n}\int\limits \cos^{n-2}x\;dx\]
It lowers the exponent by 2 each time we apply it.
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i'm coming up with \[\frac{ x }{ 16 }+\frac{ \sin2x }{ 32 }+\frac{ \sin^3[2x] }{ 48 }\]
but that doesnt check out and i cant see the flaw in my process
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