Would this be an isothermal process? A weather balloon slowly expands as energy is transferred as heat from the outside air. if the average net pressure is 1.5x10^3Pa and the balloons volume increases by 5.4x10^-5m^3, how much work is done by the expanding gas? what thermodynamic process does this situation resemble?
.081 J is the amount of work done.
I think it is because there is no change in temp. What do you think?
@douglaswinslowcooper
dU = change in internal energy = Q - pdV, where Q is heat input and pdV is work done by balloon expansion.
I think you are right and it is isothermal. It is not certain, though, as the transfer of heat will require a difference in temperature between the exterior and the interior. How that is kept constant puzzles me.
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