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find the limit as x->0 of (1-cos3h)/((cos^2)5h-1)
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just asking, did you double check the numbers?
yeah, just to be clear: find the limit as x -> 0 \[\frac{ 1-\cos3h }{ \cos ^{2}5h - 1}\]
And there is no x in that expression!
lol
Perhaps you mean h. @j88clark
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yeah
The limit is a 0/0 type which is an indeterminate form. So use the L'hospital's rule.
were supposed to be transforming it with identities
I think, @Isaiah.Feynman is correct, I cannot think of another way as well
the denominator can be re written as \[-\sin^{2}5h\]
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@j88clark
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