MEDAL GIVEN! Rewrite each expression in the form ax^n. Remember:(ax^m)^n=a^n x^mn a. (16x^28)^-5/4 b. (-32x^-30)^-6/5
a is the coefficient, x is a variable and we know that n is the power. Looking at the equation a = 16 n = -5/4 put it in the form ax^n a. ax^n = 16x^-5/4 can you solve for b.?
so i did it this method.. (16)^-5/4 and x^28^-5/4 since you have to multiply exponents 28 and -5/4 for the x the product would be x^-35 as for the 4√16^-5 i'm not sure how you would write that
would you do 2x2x2x2 which is 16 2^4 but 2^-5 isn't a clean value its a decimal
i get .03125 times x^-35 as my final answer but i'm not really positive its correct
yea 2^4 = 16. My question is once you get it in the form do you have to solve for the equation (ax^m)^n=a^n x^mn? Since the only thing i see it asks is rewrite the expression in the form ax^n. That technically doesn't mean that you have to solve for it Yea but you are doing it right
they just want you to keep it in that form and solve the value in the square root.. the reason why I wasn't sure if I did the math correct was because the 4√16^-5 was raised to a negative exponent which threw me off a little
no its correct as long as the coefficient isn't a negative number, which if it was would leave it as an imaginary number
oh ok.. because for some reason i thought maybe it would be 1/16^-5? lol and yea that makes sense because it's asking for it to be in the for ax^n
hmm i do this both ways let me see what i get but the result will be postive with a negative power
the 2 raised to the -5
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