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Biology 11 Online
OpenStudy (anonymous):

Red-green color blindness is caused by an X-linked recessive gene. In a family, the mother is a carrier of this gene while the father does not have the gene. What are the possible effects on their children? Half of the daughters are normal and half of the daughters are color-blind. Half of the boys are normal and half of the boys are color-blind. Half of the boys are color-blind and half of the girls are color-blind.

OpenStudy (anonymous):

@Carniel

OpenStudy (anonymous):

i think it is A or C

OpenStudy (carniel):

I'll let Shurti get this one

OpenStudy (shrutipande9):

hi! have u done punnet squares earlier? can u show me d genotype of both parents

OpenStudy (anonymous):

i am trying to find the information for you

OpenStudy (shrutipande9):

actually d ans is B...how did u conclude ur ans? if u want me 2 help u out wid dis crossing i can....

OpenStudy (shrutipande9):

see u need 2 work out such genetics problem....

OpenStudy (anonymous):

i was just gessing on this You are told that the mother is a carrier but not color blind herself. If she had a color blind allele on both her X chromosomes, she would be color blind. That tells you that she is heterozygous: one of her chromosomes had the normal wild type allele and the other chromosome has the allele for color blindness. The man is normal. That means he has an X with the normal wild type allele and a Y. Using the parent's genotypes, you can do a Punnet Square to see what the offspring will be like.

OpenStudy (shrutipande9):

exactly..so d mothers genotype is Xx and father XY NOW DRAW A PUNNET|dw:1392820248667:dw|

OpenStudy (shrutipande9):

Can u complete it?

OpenStudy (anonymous):

|dw:1392820235597:dw|

OpenStudy (shrutipande9):

ohh wait...lets do it this way...d recessive allele denoted by xn so mother Xxn father XY so we can differentiate..:P

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